Deutsch
Français
Español
Italiano
Português
中文
日本語
Русский
Türkçe
El Segundo Blast
Duration: 0:45
Views: 16
Submitted: 2 weeks ago
Submitted by:
Description:
Well, well, well, what Americanos got going here, BARBECUE?
Heavy g-fag presence at LAX where it is a little known secret that agent fags rig rental cars of all individuals opposing their Gestapo tactics even with miniature DEW devices but being that I engineer that lame shit under ten minutes flat, I surprise to me but let’s quantify their g-fag fire just from the video… Is that possible you wonder?
Of course I will disclose to you that based on the available information, I will analyze the explosion at the Chevron refinery by working “backward” (NOT FORWARD!) from the reported flame height by eyewitnesses on scene so while a precise, official yield is not available, I will use the observed 300-foot flames to estimate the explosion's strength so in this case reported flame height 300 feet (approximately 91 meters) with presumed cause of explosion and fire supposedly is their Isomax hydrocracking unit (jet fuel production) with my fire video footage I estimated fireball radius 91 meters which also coincides with flame height so therefore I easily quantified estimated “TNT Equivalent” (Order of Magnitude) to have been 2.5 tons of TNT using empirical relation for a hydrocarbon fireball of course… The physics behind my estimation comes from a standard empirical formula used in safety engineering and explosive yield analysis which states that the diameter of a hydrocarbon fireball in meters is approximately 3.8 times the mass of fuel in kilograms to the power of one-third, ya’ll dig’n dat? So working backward from actual AneriKKKan enemy’s flame height, the 91-meter (300-foot) flame observation is treated as the fireball radius. This gives a fireball diameter of about 182 meters…. Calculating fuel mass is easily accomplished by plugging this diameter into the formula which allows us to solve for the initial fuel mass involved in the explosion, which comes out to approximately 1,300 kilograms (about 1.3 metric tons) of hydrocarbon fuel. Whoa, that’s a lot by the way! Converting to TNT equivalent? Hydrocarbon fuels like jet fuel have a typical energy density of about 42-44 MJ/kg so the total energy release from 1,300 kg of fuel is roughly 55 Gigajoules. Since one ton of TNT releases about 4.184 Gigajoules, this energy is equivalent to 13 tons of TNT and I quantified all that JUST FROM American enemy videos, WHOA! Easy breezy! In a deflagration (a rapid fireball rather than a high-order detonation), only a fraction of the fuel contributes to the blast shockwave. A common efficiency factor I used for this AmeriKan ENEMY event is 20%. Applying this gives a final TNT equivalent blast yield of approximately 2.5 tons…
So with this American enemy refinery offline, what will be their primary replacement sources? I think that it is highly likely (fire duration variable here…) likely American enemies will need to pull more jet fuel imports from Northeast Asian refiners from their ally g-fags in South Korea, Taiwan, and Japan because according to latest data I just glanced a second ago, their American enemy Long Beach region was already receiving about 45,000-50,000 barrels per day (bpd) of jet fuel imports for their LAX G-fag FAA OK’d flight track so my market analysis suggests it will need to secure one additional cargo in the coming weeks to help compensate for the loss American low IQ’d G-fags suffered in this massive kaboom FIRE, lol!
And lastly, correlation to your FUCKIN wallet in KKKalifornia…
American g-fag agent stalker state of California’s “gasoline prices” long-term prices will remain high due to their ongoing structural challenges in their state's fuel market so in just “Days to Weeks +10 to 25 cents/gallon; potential for 35 to 95+ cents/gallon if this fire’s damage is severe + loss of 20% of Southern California's gasoline supply & their current (just glanced…) low state gasoline inventories. Seasonal refinery maintenance
Long-Term, definitely continued high prices; baseline well above national average due to planned permanent closure of other major refineries (e.g., their Phillips 66, Valero) + because of California's isolated fuel market and special blend requirements + high state taxes and environmental program costs… That’s what’chuh get with low IQ g-fags anywhere so nothing special here… The fire's impact is particularly severe because California's fuel supply chain lacks resilience and aeveral key factors create this vulnerability such as the fact that Stalkerforniuh is an "Island" Market actually due to g-fag low, low, looooow IQ.. Even fuckin Albanians are much smarter! California has limited pipeline connections to refineries in other states and requires a unique environmentally mandated gasoline blend (CARB gasoline). This makes it difficult and time-consuming to quickly replace lost supply with imports so at the pump their consumers get A$$FUCKED! Furthermore: THI$ American enemy STATE was already facing a long-term supply crisis…. Augh yeah! Their Phillips 66 refinery in the Los Angeles area is winding down operations for permanent closure and their g-fag ass kisser Valero's Benicia refinery is set to close in 2026. Together, these two closures account for roughly 20% of the state's gasoline supply so this Chevron fire exacerbates this pending shortfall and will jackhammer CA consumer asshole!
Even before this incident, California's gas prices were the highest in their American enemy nation due to a high state excise tax (currently 61.2 cents per gallon — WHOA!) and costs associated with their environmental programs like the “Low Carbon Fuel Standard” and cap-and-trade so enjoy your ga$fuck folks!
And how many g-fags will it take to put this sucker out?
That’s impossible to determine if you're an American g-fag!!
Nut if you calculate the flow rate in gallons per minute (GPM) as: RFF = (Length x Width / 3) x Number of floors so for example a single-level process unit fire covering an area of 100 feet by 100 feet, the calculation would be (100 ft x 100 ft) / 3 = approximately 3,333 GPM, therefore my simple calculation based on American enemy fire volume incorporating structure height: RFF = (Length x Width x Height) / 100. Assuming the same area and a structure height of 80 feet, the calculation is (100 ft x 100 ft x 80 ft) / 100 = 8,000 GPM but within industrial American enemy fire context these calculations of mine are likely conservative estimates because industrial fire suppression-plans often require flows greater than 5,000 GPM for major incidents and albeit this American enemy’s refinery's own fixed deluge systems are designed to release massive amounts of water in seconds, their specific capacity isn't public… But, a typical American enemy stalker Populace and agent municipal fire engine can pump around 1,500 GPM so to deliver an estimated 8,000 GPM, at least 5-6 engines would be dedicated solely to water pumping. Additional specialized apparatus like ladder trucks, command units, and ambulances would also be on scene — just in case… Firefighting operations require extensive manpower!!!! Each fire engine typically carries 3-4 firefighter g-fags so a response involving 10+ apparatus would mean 30-40 personnel just for the core firefighting tasks. This number would be higher for command, safety officers, and support roles, easily bringing the total to 50 or more — WHOA! The El Segundo and Manhattan Beach fire departments alongside Chevron's own industrial fire brigade, likely provided this level of response but a flow of 8,000 GPM would deplete a 240,000-gallon dedicated fire water tank in just 30 minutes — AUCH! Good luck wit’chuh sustained water supply AmeriKan enemy bitches!
Meanwhile, I’m enjoying AmeriKKKan enemy’s fire show again — and again!
~Stateless Warrior
Limitations of my Analysis:
My quickie-calculation assumes a "free-field" explosion in the open air. In reality, the explosion occurred within their AmeriKan ENEMY complex piping and vessels of a refinery unit. A significant portion of the blast energy would have been channeled or contained by their American stalk-prone Enemy’s “equipment” making the "felt" blast strength different from my theoretical yield because a refinery fire is not a simple, contained explosive. It involves a complex series of events where pressure builds and is released, and fuel continues to burn after the initial blast so the 300-foot flames indicate a massive, sustained fire, not just a single instantaneous explosion…. And if I had to explain this and you didn’t know it already this nano sized post is beyond your PAY GRADE BITCH!
Heavy g-fag presence at LAX where it is a little known secret that agent fags rig rental cars of all individuals opposing their Gestapo tactics even with miniature DEW devices but being that I engineer that lame shit under ten minutes flat, I surprise to me but let’s quantify their g-fag fire just from the video… Is that possible you wonder?
Of course I will disclose to you that based on the available information, I will analyze the explosion at the Chevron refinery by working “backward” (NOT FORWARD!) from the reported flame height by eyewitnesses on scene so while a precise, official yield is not available, I will use the observed 300-foot flames to estimate the explosion's strength so in this case reported flame height 300 feet (approximately 91 meters) with presumed cause of explosion and fire supposedly is their Isomax hydrocracking unit (jet fuel production) with my fire video footage I estimated fireball radius 91 meters which also coincides with flame height so therefore I easily quantified estimated “TNT Equivalent” (Order of Magnitude) to have been 2.5 tons of TNT using empirical relation for a hydrocarbon fireball of course… The physics behind my estimation comes from a standard empirical formula used in safety engineering and explosive yield analysis which states that the diameter of a hydrocarbon fireball in meters is approximately 3.8 times the mass of fuel in kilograms to the power of one-third, ya’ll dig’n dat? So working backward from actual AneriKKKan enemy’s flame height, the 91-meter (300-foot) flame observation is treated as the fireball radius. This gives a fireball diameter of about 182 meters…. Calculating fuel mass is easily accomplished by plugging this diameter into the formula which allows us to solve for the initial fuel mass involved in the explosion, which comes out to approximately 1,300 kilograms (about 1.3 metric tons) of hydrocarbon fuel. Whoa, that’s a lot by the way! Converting to TNT equivalent? Hydrocarbon fuels like jet fuel have a typical energy density of about 42-44 MJ/kg so the total energy release from 1,300 kg of fuel is roughly 55 Gigajoules. Since one ton of TNT releases about 4.184 Gigajoules, this energy is equivalent to 13 tons of TNT and I quantified all that JUST FROM American enemy videos, WHOA! Easy breezy! In a deflagration (a rapid fireball rather than a high-order detonation), only a fraction of the fuel contributes to the blast shockwave. A common efficiency factor I used for this AmeriKan ENEMY event is 20%. Applying this gives a final TNT equivalent blast yield of approximately 2.5 tons…
So with this American enemy refinery offline, what will be their primary replacement sources? I think that it is highly likely (fire duration variable here…) likely American enemies will need to pull more jet fuel imports from Northeast Asian refiners from their ally g-fags in South Korea, Taiwan, and Japan because according to latest data I just glanced a second ago, their American enemy Long Beach region was already receiving about 45,000-50,000 barrels per day (bpd) of jet fuel imports for their LAX G-fag FAA OK’d flight track so my market analysis suggests it will need to secure one additional cargo in the coming weeks to help compensate for the loss American low IQ’d G-fags suffered in this massive kaboom FIRE, lol!
And lastly, correlation to your FUCKIN wallet in KKKalifornia…
American g-fag agent stalker state of California’s “gasoline prices” long-term prices will remain high due to their ongoing structural challenges in their state's fuel market so in just “Days to Weeks +10 to 25 cents/gallon; potential for 35 to 95+ cents/gallon if this fire’s damage is severe + loss of 20% of Southern California's gasoline supply & their current (just glanced…) low state gasoline inventories. Seasonal refinery maintenance
Long-Term, definitely continued high prices; baseline well above national average due to planned permanent closure of other major refineries (e.g., their Phillips 66, Valero) + because of California's isolated fuel market and special blend requirements + high state taxes and environmental program costs… That’s what’chuh get with low IQ g-fags anywhere so nothing special here… The fire's impact is particularly severe because California's fuel supply chain lacks resilience and aeveral key factors create this vulnerability such as the fact that Stalkerforniuh is an "Island" Market actually due to g-fag low, low, looooow IQ.. Even fuckin Albanians are much smarter! California has limited pipeline connections to refineries in other states and requires a unique environmentally mandated gasoline blend (CARB gasoline). This makes it difficult and time-consuming to quickly replace lost supply with imports so at the pump their consumers get A$$FUCKED! Furthermore: THI$ American enemy STATE was already facing a long-term supply crisis…. Augh yeah! Their Phillips 66 refinery in the Los Angeles area is winding down operations for permanent closure and their g-fag ass kisser Valero's Benicia refinery is set to close in 2026. Together, these two closures account for roughly 20% of the state's gasoline supply so this Chevron fire exacerbates this pending shortfall and will jackhammer CA consumer asshole!
Even before this incident, California's gas prices were the highest in their American enemy nation due to a high state excise tax (currently 61.2 cents per gallon — WHOA!) and costs associated with their environmental programs like the “Low Carbon Fuel Standard” and cap-and-trade so enjoy your ga$fuck folks!
And how many g-fags will it take to put this sucker out?
That’s impossible to determine if you're an American g-fag!!
Nut if you calculate the flow rate in gallons per minute (GPM) as: RFF = (Length x Width / 3) x Number of floors so for example a single-level process unit fire covering an area of 100 feet by 100 feet, the calculation would be (100 ft x 100 ft) / 3 = approximately 3,333 GPM, therefore my simple calculation based on American enemy fire volume incorporating structure height: RFF = (Length x Width x Height) / 100. Assuming the same area and a structure height of 80 feet, the calculation is (100 ft x 100 ft x 80 ft) / 100 = 8,000 GPM but within industrial American enemy fire context these calculations of mine are likely conservative estimates because industrial fire suppression-plans often require flows greater than 5,000 GPM for major incidents and albeit this American enemy’s refinery's own fixed deluge systems are designed to release massive amounts of water in seconds, their specific capacity isn't public… But, a typical American enemy stalker Populace and agent municipal fire engine can pump around 1,500 GPM so to deliver an estimated 8,000 GPM, at least 5-6 engines would be dedicated solely to water pumping. Additional specialized apparatus like ladder trucks, command units, and ambulances would also be on scene — just in case… Firefighting operations require extensive manpower!!!! Each fire engine typically carries 3-4 firefighter g-fags so a response involving 10+ apparatus would mean 30-40 personnel just for the core firefighting tasks. This number would be higher for command, safety officers, and support roles, easily bringing the total to 50 or more — WHOA! The El Segundo and Manhattan Beach fire departments alongside Chevron's own industrial fire brigade, likely provided this level of response but a flow of 8,000 GPM would deplete a 240,000-gallon dedicated fire water tank in just 30 minutes — AUCH! Good luck wit’chuh sustained water supply AmeriKan enemy bitches!
Meanwhile, I’m enjoying AmeriKKKan enemy’s fire show again — and again!
~Stateless Warrior
Limitations of my Analysis:
My quickie-calculation assumes a "free-field" explosion in the open air. In reality, the explosion occurred within their AmeriKan ENEMY complex piping and vessels of a refinery unit. A significant portion of the blast energy would have been channeled or contained by their American stalk-prone Enemy’s “equipment” making the "felt" blast strength different from my theoretical yield because a refinery fire is not a simple, contained explosive. It involves a complex series of events where pressure builds and is released, and fuel continues to burn after the initial blast so the 300-foot flames indicate a massive, sustained fire, not just a single instantaneous explosion…. And if I had to explain this and you didn’t know it already this nano sized post is beyond your PAY GRADE BITCH!
Categories:
People and Blogs
